MCQ
The collector current in a common base amplifier using $n-p-n$ transistor is $24\; mA$. If $80 \%$ of the electrons released by the emitter is accepted by the collector, then the base current is numerically
- A$6\,mA$ and leaving the base
- B$3\,mA$ and leaving the base
- ✓$6\,mA$ and entering the base
- D$3\,mA$ and entering the base
