MCQ
The correct order of the increasing ionic character is
- ✓$BeC{l_2} < MgC{l_2} < CaC{l_2} < BaC{l_2}$
- B$BeC{l_2} < MgC{l_2} < BaC{l_2} > CaC{l_2}$
- C$BeC{l_2} < BaC{l_2} < MgC{l_2} < CaC{l_2}$
- D$BaC{l_2} < CaC{l_2} < MgC{l_2} < BeC{l_2}$
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The final product formed in the above reaction sequence is
Product $(A)$ of the above reaction is


$\begin{array}{|l|l|} \hline \,\,List\,\,\,\,I\,\,(Compound) & \,\,List\,\,II\,\,(Oxidation\,\,state\,\,of\,\,N) \\ \hline (A)\,\,N{{O}_{2}} & (1)\,\,\,\,+\,\,5 \\ \hline (B)\,\,HNO & (2)\,\,-\,\,3 \\ \hline (C)\,\,N{{H}_{3}} & (3)\,\,+\,\,4 \\ \hline (D)\,\,{{N}_{2}}{{O}_{5}} & (4)\,\,+\,\,1 \\ \hline \end{array}$
code : $A \,\, B \,\,C \,\,D$