The current flowing through the $1 \Omega$ resistor is $\frac{\mathrm{n}}{10} \ A. $ The value of $n$ is. . . . . . .
JEE MAIN 2024, Diffcult
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$\frac{y-5}{2}+\frac{y-0}{2}+\frac{y-x+10}{1}=0$
$y-5+y+2 y-2 x+20=0$
$4 y-2 x+15=0 \quad \ldots .(i)$
$\frac{x-5}{4}+\frac{x-0}{4}+\frac{x-10-y}{1}=0$
$x-5+x+4 x-40-4 y=0$
$6 x-4 y-45=0 \quad . .(i)$
$\frac{-2 x+4 y+15=0 . .(i i)}{4 x-30=0}$
$x=\frac{15}{2} \& 4 y-15+15=0$
$y=0$
$i=\frac{y-x+10}{1}$
$i=\frac{0-7.5+10}{1}$
$i=2.5 A=\frac{n}{10} A$
$n=25$
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