b
In steady state capacitor is fully charged hence no current will flow through line $2$ .
Bysimplyfing the circuit
Hence resultant potential difference across resistances will be $8.0 \,\mathrm{V}$
Thus current $1=\frac{V}{R}=\frac{8.0}{3+9}=\frac{8}{12}$
or, $\quad I=\frac{2}{3}=0.67\, \mathrm{A}$
