MCQ
The efficiency of Carnot engine when source temperature is $T_1$ and sink temperature is $T_2$ will be
- ✓$\frac{{{T_1} - {T_2}}}{{{T_1}}}$
- B$\frac{{{T_2} - {T_1}}}{{{T_2}}}$
- C$\frac{{{T_1} - {T_2}}}{{{T_2}}}$
- D$\frac{{{T_1}}}{{{T_2}}}$
✓
Answer
Correct option: A.
$\frac{{{T_1} - {T_2}}}{{{T_1}}}$
a
(a) Efficiency of Carnot engine $=\eta=\frac{T_{1}-T_{2}}{T_{1}}$
(a) Efficiency of Carnot engine $=\eta=\frac{T_{1}-T_{2}}{T_{1}}$
where, $T_{1}=$ source temperature
$T_{2}=$ sink temperature
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