$\omega_{\text {old }}=\sqrt{\frac{k_{\text {old }}}{m}}$
When divided into $3$ parts the spring constant of smaller parts
$\therefore k_{\text {final }}=3 k_{\text {old }}$
$\therefore \omega_{\text {linal }}=\sqrt{3} \omega_{\text {old }}$
$\omega=2 \pi v$
Hence $v_{\text {final }}=\sqrt{3} v_{\text {old }} \Rightarrow v_2=\sqrt{3} v_1$
$(A)$ Restoring torque in case $A =$ Restoring torque in case $B$
$(B)$ Restoring torque in case $A < $ Restoring torque in case $B$
$(C)$ Angular frequency for case $A > $ Angular frequency for case $B$.
$(D)$ Angular frequency for case $A < $ Angular frequency for case $B$.


$x = a\,\sin \,\left( {\omega t + \pi /6} \right)$
After the elapse of what fraction of the time period the velocity of the particle will be equal to half of its maximum velocity?