MCQ
The incorrect statement regarding $15^{th}$ group hydrides $(EH_3)$ . $[E = N, P, As, Sb, Bi]$
  • A
    $NH_3 > PH_ 3 > AsH_ 3 > SbH_ 3 > BiH_ 3 :$ Thermal stability
  • B
    $N-H > P-H > As-H > Sb-H > Bi-H : E-H$ bond dissociation enthalpy
  • $NH_3 > PH_3 > AsH_3 > SbH_3 > BiH_3 :$ Reducing character
  • D
    $NH_3 > PH_3 > AsH_3 > SbH_3 > BiH_3 :$ Basicity

Answer

Correct option: C.
$NH_3 > PH_3 > AsH_3 > SbH_3 > BiH_3 :$ Reducing character
c
${\text{Reducing character}} \propto \frac{1}{{'E - H'\,bond\,dissociation\,enthalpy}}$

Hence, correct reducing character is $NH_3 < PH_3 < AsH_3 < SbH_3 < BiH_3$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

$\begin{array}{*{20}{c}}
  O \\ 
  {||} \\ 
  {H - C - Cl} 
\end{array}$ is called
Replacement of $Cl$ of chlorobenzene to give phenol requires drastic conditions but chlorine of $2,\,4-$ dinitrochlorobenzene is readily replaced because.
$CuS{O_4}$ reacts with $KCN$  solution and forms:
What is $Z$ in the following sequence of reaction

$Z\xrightarrow{{PC{l_5}}}X\xrightarrow{{Alc.KOH}}Y\xrightarrow{{dil{H_2}S{O_4}}}Z$

Number of ambidentate ligands in a representative metal complex $\left[ M ( en )( SCN )_4\right]$ is $\text { [en }=\text { ethylenediamine }]$
Which of the following represent free radical substitution reaction $(FSR)$, electrophilic addition reaction $(EAR)$ and nucleophilic addition reaction $(NAR)$

$I.$ $CH_3 -CH = CH_2$ $\xrightarrow[{{\text{(CC}}{{\text{l}}_4}{\text{ )}}}]{{{\text{C}}{{\text{l}}_2}}}$ $\begin{array}{*{20}{c}}
{Cl\,\,}\\
{\,\,|\,\,\,\,\,}\\
{C{H_3} - CH - C{H_2}}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl}
\end{array}$

$II.$ $\begin{array}{*{20}{c}}
O\\
{||}\\
{C{H_3} - C - C{H_3}}
\end{array}$ $\xrightarrow[{{}^\Theta OH}]{{{\text{HCN}}}}$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,OH}\\
|\\
{C{H_3} - C - C{H_3}}\\
|\\
{\,\,\,\,\,CN}
\end{array}$

$III.$ $CH_3-CH_2-CH_3$ $\xrightarrow[{hv}]{{C{l_2}}}$ $\begin{array}{*{20}{c}}
{Cl\,\,}\\
{|\,\,\,\,}\\
{C{H_3} - CH - C{H_3}}
\end{array}$

Which is incorrect
Relative lowering of vapour pressure of a solution is equal to:
Which of the following is capable of forming a zwitter ion
An organic compound answers Molisch's test as well as Benedict's test. But it does not answer Scliwanoff's test. Most probably, it is