
$R_{e q \text { closed }}=2 \times \frac{R \times 2 R}{3 R}=\frac{4 R}{3}$
$\frac{{R}_{\text {eq open }}}{{R}_{\text {eq closed }}}=\frac{3 R}{2} \times \frac{3}{4 {R}}=\frac{9}{8}$
$\therefore \quad {X}=9$
What is the value of current at $t = 4\,s$ ? ............... $\mu A$



