The total momentum of electrons in a straight wire of copper of length $1\, metre$ carrying a current of $16\, A$ is
A$91 \times 10^{-12}\, kg\, m/sec$
B$91 \times 10^{-15}\, kg\, m/sec$
C$91 \times 10^{-14}\, kg\, m/sec$
D$91 \times 10^{-6}\, kg\, m/sec$
Medium
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A$91 \times 10^{-12}\, kg\, m/sec$
a $P = nMe{V_d} = \left[ {\frac{{iL}}{e}} \right]\,Me$
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