The value of current through the $20\,\Omega $ resistor is ............ $amp$
Medium
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$\frac{x-10}{10}+\frac{x+6}{20}+\frac{x}{10}+\frac{x-10}{5}=0$
$\Rightarrow \mathrm{x}=6 \mathrm{\,V}$
$\therefore \mathrm{I}_{20 \Omega}=\frac{6+6}{20}=0.6 \mathrm{\,Amp}$
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