MCQ
The value of one Faraday is .............. ${\rm{C}}\,{\rm{mo}}{{\rm{l}}^{ - 1}}$
- A$95500$
- B$96550$
- ✓$96500$
- D$98500$
therefore the Answer is $96500 \,Cm ^{-1}$
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$3HCHO+A\xrightarrow[{{40}\,^{o}}C]{N{{a}_{2}}C{{O}_{3}}}\underset{(82\%)}{\mathop{(B)}}$
Product $(B)$ of the above reaction is

Reason : Rate of reaction remains constant during the course of reaction.