The variation of kinetic energy $(KE)$ of a particle executing simple harmonic motion with the displacement $(x)$ starting from mean position to extreme position $(A)$ is given by
JEE MAIN 2023, Medium
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For a particle executing SHM
$KE =\frac{1}{2} m \omega^2\left( A ^2- x ^2\right)$
When $x =0, KE$ is maximum and when $x = A , KE$ is zero and $KE V / S x$ graph is parabola.
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