MCQ
The work function of cesium metal is 2eV. It means that 
  • A
    The energy necessary to emit electrons from metal surface is 2eV
  • B
    The energy of electrons emitted from metallic surface is 2eV
  • C
    The value of photoelectric current is 2eV
  • D
    The value of threshold frequency is 2eV

Answer

  1. The energy necessary to emit electrons from metal surface is 2eV

Explanation:

By definition  the work function is the minimum energy (in electron volts) needed to remove an electron from a solid to a point immediately outside the solid surface (or energy needed to move an electron from the Fermi level into vacuum).

Hence, if the work function of cesium metal is 2ev, it means that the energy necessary to emit electrons from metal surface is 2eV.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

When a proton is accelerated with 1 volt potential difference, then its kinetic energy is

(a)  

(b) 1840 eV

(c) 1 eV   

(d) 1840 c2 eV

The stopping potential V for photoelectric emission from a metal surface is plotted along Y-axis and frequency n of incident light along X-axis. A straight line is obtained as shown. Planck's constant is given by

(a) Slope of the line

(b) Product of slope on the line and charge on the electron

(c) Product of intercept along Y-axis and mass of the electron

(d) Product of Slope and mass of electron

Angle of prism is A and its one surface is silvered. Light rays falling at an angle of incidence 2A on first surface return back through the same path after suffering reflection at second silvered surface. Refractive index of the material of prism is

(a) 2 sin A

(b) 2 cos A

(c)  

(d) tan A

5 amperes of current is passed through a metallic conductor. The charge flowing in one minute in coulombs will be

(a) 5 

(b) 12

(c) 1/12

(d) 300

A solid at temperature T1 is kept in an evacuated chamber at temperature $\text{T}_2>\text{T}1.$ The rate of increase of temperature of the body is proportional to:
  1. $\text{T}_2-\text{T}_1$
  2. $\text{T}_2^2-\text{T}_1^2$
  3. $\text{T}_2^3-\text{T}_1^3$
  4. $\text{T}_2^4-\text{T}_1^4$
Statement-I : Energy is released when heavy nuclei undergo fission or light nuclei undergo fusion and

Statement-II: For heavy nuclei, binding energy per nucleon increases with increasing Z. while for light nuclei it decreases with increasing Z.

Curies law can be written as

(a) x (T -

(b) x  

(c) x   

(d) x T

For a particle executing simple harmonic motion, the acceleration is proportional to:
  1. Displacement from the mean position.
  2. Distance from the mean position.
  3. Distance travelled since t = 0.
  4. Speed.

Let V and H be the vertical and horizontal components of earth's magnetic field at any point on earth. Near the north pole

(a) V >> H

(b) V << H

(c) V = H  

(d) V = H = 0

In YDSE, the slit widths are in the ratio of 1:9. The ratio of intensity of the maxima to that of the minima is: