Question
The Young’s modulus for steel is much more than that for rubber. For the same longitudinal strain, which one will have greater tensile stress?
✓
Answer
$\text{Y}=\frac{\text{stress}}{\text{strain}}$ As per question longitudinal strain for rubber and steel are equal. $\therefore\text{Y}\propto\text{stress}$ $\therefore\frac{\text{Y}_\text{steel}}{\text{Y}_\text{Rubber}}=\frac{\text{(stress})_\text{steel}}{\text{(stress})_\text{Rubber}}\text{ As the Y}_\text{steel}>\text{Y}_\text{Rubber}$ $\therefore\frac{\text{Y}_\text{steel}}{\text{Y}_\text{Rubber}}>1$ $\therefore\text{(stress})_\text{steel}$ is larger than $(Stress)_{Rubber}$
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