There are $n$ similar conductors each of resistance $R$. The resultant resistance comes out to be $x$ when connected in parallel. If they are connected in series, the resistance comes out to be
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(b)In parallel, $x = \frac{R}{n}$ $R = nx$
In series, $R + R + R$ .... $n$ times $=$ $nR = n (nx) = n^2x$
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