There is a current of $20$ amperes in a copper wire of ${10^{ - 6}}$ square meter area of cross-section. If the number of free electrons per cubic meter is ${10^{29}}$, then the drift velocity is
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(c) ${v_d} = \frac{i}{{nAe}} = \frac{{20}}{{{{10}^{29}} \times {{10}^{ - 6}} \times 1.6 \times {{10}^{ - 19}}}}$$ = 1.25 \times {10^{ - 3}}\,m/s$
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