Three resistors having resistances $\mathrm{r}_{1}, \mathrm{r}_{2}$ and $\mathrm{r}_{3}$ are connected as shown in the given circuit. The ratio $\frac{i_{3}}{i_{1}}$ of currents in terms of resistances used in the circuit is :
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$I_{3}=\frac{I_{1} r_{2}}{r_{2}+r_{3}}$
$\frac{I_{3}}{I_{1}}=\frac{I_{1} r_{2}}{\left(r_{2}+r_{3}\right) I_{1}}=\frac{r_{2}}{r_{2}+r_{3}}$
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