Time period of pendulum, on a satellite orbiting the earth, is
A$1 / \pi$
B
zero
C$\pi$
D
infinity
AIIMS 2016, Easy
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D
infinity
d (d)
As we know, $T \alpha \frac{1}{\sqrt{ g }}$
On a artificial satellite, orbiting the earth, neg gravity is zero. As,
$\Rightarrow \quad g =0 \Rightarrow T \rightarrow \infty$
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