To show that a simple pendulum executes simple harmonic motion, it is necessary to assume that
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(c)If amplitude is large motion will not remain simple harmonic.
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The time period of a second's pendulum is $2\, sec$. The spherical bob which is empty from inside has a mass of $50\, gm$. This is now replaced by another solid bob of same radius but having different mass of $ 100\, gm$. The new time period will be .... $\sec$
The displacement of a particle undergoing $SHM$ of time period $T$ is given by $x(t) = x_m\,cos\, (\omega t + \phi )$. The particle is at $x = -x_m$ at time $t = 0$. The particle is at $x = + x_m$ when
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