Twelve wires of equal length and same cross-section are connected in the form of a cube. If the resistance of each of the wires is $R$, then the effective resistance between the two diagonal ends would be
A$2\,R$
B$12\,R$
C$\frac{5}{6}R$
D$8\,R$
Medium
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C$\frac{5}{6}R$
c (c) The given circuit can be simplified as follows
${R_{AD}} = \frac{{5R}}{6}$
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