Two conductors made of the same material are connected across a common potential difference. Conductor $A$ has twice the diameter and twice the length of conductor $B$. The power delivered to the two conductors ${P_A}$ and ${P_B}$ respectively is such that ${P_A}/{P_B}$ equals to
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(d) $R = \rho \frac{l}{A}$and$P \propto \frac{1}{R}$$⇒$$P \propto \frac{A}{l}$$⇒$$P \propto \frac{{{d^2}}}{l}$ $⇒$${P_A} = 2{P_B}$
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