Two electric bulbs whose resistance are in the ratio of $1: 2$, are connected in parallel to a constant voltage source. The power dissipated in them has the ratio
A$2: 1$
B$1: 1$
C$1: 4$
D$1: 2$
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A$2: 1$
a (a)
$P=\frac{V^2}{R}$
$P \propto \frac{1}{R}$
$\frac{P_1}{P_2}=\frac{R_2}{R_1}=\frac{2}{1}$
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