MCQ
Two insulating plates are both uniformly charged in such a way that the potential difference between them is $V_2 - V_1 = 20\ V$. (i.e., plate $2$ is at a higher potential). The plates are separated by $d = 0.1\ m$ and can be treated as infinitely large. An electron is released from rest on the inner surface of plate $1. $ What is its speed when it hits plate $2?$
$(e = 1.6 \times 10^{-19}\ C, m_e= 9.11 \times 10^{-31}\ kg)$
  • A
    $32 \times 10^{-19} $ $m/s$
  • $2.65 \times 10^6 $ $m/s$
  • C
    $7.02 \times 10^{12}$ $ m/s$
  • D
    $1.87 \times 10^6 $ $m/s$

Answer

Correct option: B.
$2.65 \times 10^6 $ $m/s$
b
${e V=\frac{1}{2} m v^{2}}$

${\Rightarrow v=\sqrt{\frac{2 e V}{m}}=\sqrt{\frac{2 \times 1.6 \times 10^{-19} \times 20}{9.1 \times 10^{-31}}}}$

${=2.65 \times 10^{6} \,\mathrm{m} / \mathrm{s}}$

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