Two resistors are joined in parallel whose, resultant is $\frac{6}{5} \,\Omega$. One of the resistance wire is broken and the effective resistance becomes $2 \,ohms$. Then the resistance (in $ohm$) of the wire that got broken is ..........
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(d)
$\frac{R_1 R_2}{R_1+R_2}=\frac{6}{5}$
$R_1=2$
$\frac{2 R_2}{2+R_2}=\frac{6}{5}$
$5 R_2=6+3 R_2$
$2 R_2=6$
$R_2=3 \,\Omega$
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