Two springs of force constants $K$ and $2K$ are connected to a mass as shown below. The frequency of oscillation of the mass is
  • A$(1/2\pi )\sqrt {(K/m)} $
  • B$(1/2\pi )\sqrt {(2K/m)} $
  • C$(1/2\pi )\sqrt {(3K/m)} $
  • D$(1/2\pi )\sqrt {(m/K)} $
AIIMS 2003, Medium
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    Force constant of a spring is $K$ . If half part is detached then force constant of the remaining spring will be
    View Solution
  • 2
    The frequency of oscillation of the springs shown in the figure will be
    View Solution
  • 3
    Equations ${y_1} = A\sin \omega t$ and ${y_2} = \frac{A}{2}\sin \omega t + \frac{A}{2}\cos \omega t$ represent $S.H.M.$ The ratio of the amplitudes of the two motions is
    View Solution
  • 4
    In a simple pendulum, the period of oscillation $T$ is related to length of the pendulum $l$ as
    View Solution
  • 5
    A simple pendulum of mass $m$ executes $S.H.M.$ with total energy $E$. If at an instant it is at one of extreme positions, then its linear momentum after a phase shift of $\frac{\pi}{3} \,rad$ will be
    View Solution
  • 6
    A body is performing simple harmonic motion with amplitude a and time period $T$. Variation of its acceleration $(f)$ with time $(t)$ is shown in figure. If at time $t$, velocity of the body is $v$, which of the following graphs is correct
    View Solution
  • 7
    The height of liquid column in a $U$ tube is $0.3$ meter. If the liquid in one of the limbs is depressed and then released, then the time period of liquid column will be $.......\,sec$ 
    View Solution
  • 8
    In case of a forced vibration, the resonance wave becomes very sharp when the
    View Solution
  • 9
    Two simple harmonic motions are represented by the equations

    ${x}_{1}=5 \sin \left(2 \pi {t}+\frac{\pi}{4}\right)$ and ${x}_{2}=5 \sqrt{2}(\sin 2 \pi {t}+\cos 2 \pi {t})$

    The amplitude of second motion is ....... times the amplitude in first motion.

    View Solution
  • 10
    A particle executes simple harmonic motion. Its amplitude is $8 \,cm$ and time period is $6 \,s$. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is ............. $s$
    View Solution