MCQ
What will be $r.m.s.$ value of given $A.C.$ over one cycle.
- A${V_0}$
- B$\frac{{{V_0}}}{{\sqrt 2 }}$
- ✓$\frac{{{V_0}}}{2}$
- D$\frac{{{V_0}}}{4}$
✓
Answer
Correct option: C.
$\frac{{{V_0}}}{2}$
c
$(\mathrm{RMS})^{2}=\frac{\int_{0}^{\mathrm{T} / 2} \mathrm{V}_{0}^{2} \sin ^{2} \mathrm{td} \mathrm{t}}{\mathrm{T}}=\frac{\mathrm{V}_{0}^{2}}{4}$
$(\mathrm{RMS})^{2}=\frac{\int_{0}^{\mathrm{T} / 2} \mathrm{V}_{0}^{2} \sin ^{2} \mathrm{td} \mathrm{t}}{\mathrm{T}}=\frac{\mathrm{V}_{0}^{2}}{4}$
So $\mathrm{RMS}=\mathrm{V}_{0} / 2$
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