When a potential difference $V$ is applied across a wire of resistance $R$, it dissipates energy at a rate $W$. If the wire is cut into two halves and these halves are connected mutually parallel across the same supply, the same supply, the energy dissipation rate will become:
JEE MAIN 2024, Diffcult
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$ \frac{\mathrm{v}^2}{\mathrm{R}}=\mathrm{W}$ $....(i)$
$\frac{\mathrm{v}^2}{\frac{1}{2}\left(\frac{\mathrm{R}}{2}\right)}=\mathrm{W}^{\prime}$ $...(ii)$
From $(i)$&$(ii)$, we get
$W^{\prime}=4 W$
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