- A$Mg\,{(OH)_2}$
- B$Ca\,{(OH)_2}$
- C$Ba\,{(OH)_2}$
- ✓$Be\,{(OH)_2}$
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$(A)\,S_{\left( g \right)}^ - \,\, \to \,\,S_{\left( g \right)}^{2 - }\,$
$(B)\,Na_{\left( g \right)}^ + \, + \,Cl_{\left( g \right)}^ - \,\, \to \,\,NaCl\,(s)$
$(C)\,{N_{\left( g \right)}}\, \to \,\,N_{\left( g \right)}^ - $
$(D)\,Al_{\left( g \right)}^{2 + }\, \to \,\,Al_{\left( g \right)}^{3 + }$

Statement $(I)$ : Oxygen being the first member of group $16$ exhibits only $-2$ oxidation state.
Statement $(II)$ : Down the group $16$ stability of $+4$ oxidation state decreases and $+6$ oxidation state increases.
In the light of the above statements, choose the most appropriate answer from the options given below:
(Use $R =8.31\, J\, K ^{-1}\, mol ^{-1} ; \log 2=0.3010$. In $10=$ $2.3, \log 3=0.477$ )
$Pt:\frac{1}{2}\,{H_2}\left( g \right)\,|{H^ + }\left( {{{10}^{ - 8}}\,M} \right)||{H^ + }\,\left( {{{10}^{ - 3}}\,M} \right)|\frac{1}{2}\,{H_2}\left( g \right)\,;Pt$