- A

- B

- C

- D





Explanation:

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$1.$ The compound ${X}$ is
$(A)$ $\mathrm{NaNO}_3$ $(B)$ $\mathrm{NaCl}$ $(C)$ $\mathrm{Na}_2 \mathrm{SO}_4$ $(D)$ $\mathrm{Na}_2 \mathrm{~S}$
$2.$ The compound ${Y}$ is
$(A)$ $\mathrm{MgCl}_2$ $(B)$ $\mathrm{FeCl}_2$ $(C)$ $\mathrm{FeCl}_3$ $(D)$ $\mathrm{ZnCl}_2$
$3.$ The compound ${Z}$ is
$(A)$ $\left.\mathrm{Mg}_2 \mid \mathrm{Fe}(\mathrm{CN})_6\right]$ $(B)$ $\operatorname{Fe}\left[\mathrm{Fe}(\mathrm{CN})_6\right]$
$(C)$ $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$ $(D)$ $\mathrm{K}_2 \mathrm{Zn}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2$
Give the answer question $1,2$ and $3.$
${\lambda _{NaCl}} = 38.2\;oh{m^{ - 1}}\,c{m^2}\,gme{q^{ - 1}}$,
${\lambda _{HCl}} = 203\;oh{m^{ - 1}}\,c{m^2}\,gme{q^{ - 1}}$,
What is the value of ${\lambda _{ClC{H_2}COOH}}$ .............. ${\rm{Oh}}{{\rm{m}}^{ - 1}}{\mkern 1mu} {\rm{c}}{{\rm{m}}^2}{\rm{gm}}\,{\rm{e}}{{\rm{q}}^{ - 1}}$
$R-Cl\xrightarrow{(i)\,\,KCN,(ii)\,LiAl{{H}_{4}}} $ Product $A$
$R-Cl\xrightarrow{(i)\,\,AgCN,(ii)\,LiAl{{H}_{4}}} $ Product $B $
the compounds $A$ and $B$ are
$Cr_2O_7^{2-}$ ( $aq$ $1\,M$ ) $+ 14H^+(aq) + 6e^-$ $\rightarrow 2Cr^{+3} (aq,\,1\,M) + 7H_2O (l)$