MCQ
Work done per mol in an isothermal change is
- A$RT{\log _{10}}\frac{{{V_2}}}{{{V_1}}}$
- B$RT{\log _{10}}\frac{{{V_1}}}{{{V_2}}}$
- ✓$RT{\log _e}\frac{{{V_2}}}{{{V_1}}}$
- D$RT{\log _e}\frac{{{V_1}}}{{{V_2}}}$
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