Download App

Statistics — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsStatistics1 Mark
MCQ
Write the correct answer in the following:
The class marks of a frequency distribution are given as follows: 15, 20, 25, .... The class corresponding to the class mark 20 is:
  • A
    12.5 - 17.5
  • B
    17.5 - 22.5
  • C
    18.5 - 21.5
  • D
    19.5 - 20.5
✓

Answer

  1. 17.5 - 22.5

Solution:

The class mark are 15, 20, 25, ….

The size of each class interval is 25 - 20 = 20 - 15 = 5

Hence, the class interval corresponding to the class mark 20 is,

(20 - 2.5) - (20 + 2.5) i.e., 17.5 - 22.5.

So, (b) is the correct answer.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q" from Statistics→Statistics — all question types→Maths STD 9 question papers→Gujarat Board STD 9 question papers→Gujarat Board question paper generator→

Similar questions

The number of cubes of side 3cm that can be cut from a cuboid of dimensions 10cm × 9cm × 6cm, is:
  1. 9
  2. 10
  3. 18
  4. 20
→
Any point on the line y = 3x is of the form.
→
Less than’ cumulative frequency table for a given data is as follows. Then, the frequency of class interval 20-30 is:
Marks
Less than 10
Less than 20
Less than 300
Less than 40
Cumulative frequency
3
17
37
92
→
The height of a conical vessel is 3.5cm. If its capacity is 3.3 litres of milk, then the diameter of its base is:
→
$\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$ is equal to :
→
If 10x - 4x2 - 3, then the value of p(0) + p(1) is:
→
If x + a is a factor of x4 - a2x2 + 3x - 6a, then a =
→
The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8cm and 6cm is:
  1. A rhombus of area 24cm2
  2. A rectangle of area 24cm2
  3. A square of area 26cm2
  4. A trapezium of area 14cm2
→
The surface area of a sphere of radius 3.5cm is:
→
The sum of the length, breadth and depth of a cuboid is 19cm and its diagonal is $5\sqrt{5}$. Its surface area is.
→