- Aboth give out $O_2$
- B$XeF_6$ gives $O_2$ and $XeF_2$ does not
- ✓$XeF_2$ alone gives $O_2$
- DNeither of them gives $HF$
$\mathrm{XeF}_{6}+3 \mathrm{H}_2O \stackrel{\mathrm{R.T}}{\longrightarrow} \mathrm{XeO}_{3}+6 \mathrm{HF}$
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$Mn{O_2}(s)\, + \,4{H^ + }(aq)\, + \,2{e^ - }\, \to \, M{n^{ + 2}}(aq)\, + \,2{H_2}O(l)\,;$ $E_2^o\, = \,1.21\,\,V$
$MnO_4^{ - 1}(aq)\, + \,4{H^ + }(aq)\, + \,3{e^ - }\, \to \, Mn{O_2}(s)\, + \,3{H_2}O(l)\,;$ $E_3^o\,?$
value of $E_3^o$ will be ............ $\mathrm{V}$
$A$. A liquid evaporates to vapour.
$B$. Temperature of a crystalline solid lowered from $130 \mathrm{~K}$ to $0 \mathrm{~K}$.
$C$. $2 \mathrm{NaHCO}_{3(\mathrm{~s})} \rightarrow \mathrm{Na}_2 \mathrm{CO}_{3(\mathrm{~s})}+\mathrm{CO}_{2(\mathrm{~g})}+\mathrm{H}_2 \mathrm{O}_{(\mathrm{g})}$
$D$. $\mathrm{Cl}_{2(g)} \rightarrow 2 \mathrm{Cl}_{(g)}$
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