Two identical metallic balls, whose temperatures are $200^{\circ} C$ and $400^{\circ} C$ respectively, are placed in an enclosure at $27^{\circ} C$. The ratio of heat-loss of the balls will be
- A$1: 4$
- B$\frac{(473)^4-(300)^4}{(673)^4-(300)^4}$
- C$1: 2$
- D$\frac{(200)^4-(27)^4}{(400)^4-(27)^4}$

