A battery has $e.m.f.$ $4\, V$ and internal resistance $r$. When this battery is connected to an external resistance of $2\, ohms$, a current of $1\, amp$. flows in the circuit. How much current will flow if the terminals of the battery are connected directly .......... $amp$
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(b) $i = \frac{E}{{R + r}} \Rightarrow 1 = \frac{4}{{2 + r}} = r = 2\,\Omega $
Short circuit when terminals of battery connected directly then current flows which is ${i_{SC}} = \frac{E}{r} = \frac{4}{2} = 2\,A$.
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