A cell of internal resistance $3\, ohm$ and $emf$ $10\, volt$ is connected to a uniform wire of length $500 \,cm$ and resistance $3\, ohm$. The potential gradient in the wire is .............. $mV/cm$
Medium
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(b) Potential gradient = $\frac{{e.R}}{{(R + r).L}}$= $\frac{{10 \times 3}}{{(3 + 3) \times 5}}$.
$ = 1V/m = 10\,mV/cm.$
$ = 1V/m = 10\,mV/cm.$
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