An electric toaster has resistance of $60\ \Omega$ at room temperature $\left(27^{\circ} \mathrm{C}\right)$. The toaster is connected to a $220 \mathrm{~V}$ supply. If the current flowing through it reaches $2.75 \mathrm{~A}$, the temperature attained by toaster is around : (if $\alpha=2 \times 10^{-4} /{ }^{\circ} \mathrm{C}$ )
JEE MAIN 2024, Diffcult
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$ \mathrm{R}_{\mathrm{T}=27}=60 \Omega, R_T=\frac{220}{2.75}=80 \Omega $
$ \mathrm{R}=\mathrm{R}_0(1+\alpha \Delta \mathrm{T}) $
$ 80=60\left[1+2 \times 10^{-4}(\mathrm{~T}-27)\right] $
$ \mathrm{T} \approx 1694^{\circ} \mathrm{C}$
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