$\mathrm{f}_2=\frac{1}{2 \pi} \sqrt{\frac{\mathrm{k}}{9 \mathrm{~m}}}$
$\frac{\mathrm{f}_1}{\mathrm{f}_2}=\sqrt{\frac{9}{1}}=\frac{3}{1}$
$y_{2}=5(\sin 3 \pi t+\sqrt{3} \cos 3 \pi t)$
Ratio of amplitude of ${y}_{1}$ to ${y}_{2}={x}: 1$. The value of ${x}$ is ...... .