A particle executes $S.H.M.$ of amplitude A along $x$-axis. At $t =0$, the position of the particle is $x=\frac{A}{2}$ and it moves along positive $x$-axis the displacement of particle in time $t$ is $x=A \sin (\omega t+\delta)$, then the value $\delta$ will be
JEE MAIN 2023, Medium
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$y\left( t \right) = B\,\sin \,\left( {bt} \right)$
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