The displacement of a particle is represented by the equation $y = sin^3\,\,\,\omega t$ . The motion is
  • A
    non- periodic
  • B
    periodic but not simple harmonic
  • Csimple harmonic with period $\frac {2 \pi }{\omega }$
  • Dsimple harmonic with period $\frac {\pi }{\omega }$
Medium
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    A particle of mass $200 \,gm$ executes $S.H.M.$ The restoring force is provided by a spring of force constant $80 \,N / m$. The time period of oscillations is .... $\sec$
    View Solution
  • 2
    A particle performs $SHM$ about $x = 0$ such that at $t = 0$ it is at $x = 0$ and moving towards positive extreme. The time taken by it to go from $x = 0$ to $x = \frac{A}{2}$ is ..... times the time taken to go from $x = \frac{A}{2}$ to $A$. The most suitable option for the blank space is
    View Solution
  • 3
    When a mass $m$ is attached to a spring, it normally extends by $0.2\, m$. The mass $m$ is given a slight addition extension and released, then its time period will be
    View Solution
  • 4
    The displacement $x$ (in metre) of a particle in, simple harmonic motion is related to time t (in seconds) as

    $x = 0.01\cos \left( {\pi \,t + \frac{\pi }{4}} \right)$

    The frequency of the motion will be

    View Solution
  • 5
    The amplitude of a wave represented by displacement equation

    $y = \frac{1}{{\sqrt a }}\,\sin \,\omega t \pm \frac{1}{{\sqrt b }}\,\cos \,\omega t$ will be

    View Solution
  • 6
    A body of mass $0.01 kg$ executes simple harmonic motion $(S.H.M.)$ about $x = 0$ under the influence of a force shown below : The period of the $S.H.M.$ is .... $s$
    View Solution
  • 7
    If the maximum velocity and maximum acceleration of a particle executing $SHM$ are equal in magnitude, the time period will be .... $\sec$
    View Solution
  • 8
    In S.H.M. maximum acceleration is at
    View Solution
  • 9
    Acceleration of a particle, executing $SHM$, at it’s mean position is
    View Solution
  • 10
    A body oscillates with $S.H.M.$ according to the equation $x=(5.0 \,m ) \cos \left[\left(2 \pi \,rad s ^{-1}\right) t+\pi / 4\right]$ At $t=1.5 \,s$, its acceleration is ....... $m / s ^2$
    View Solution