MCQ
A reaction rate constant is given by $k = 1.2 \times 10^{14} \,e^{-25000/RT} \,sec^{-1}$.It means
- A$\log\, k$ versus $\log\, T$ will give a straight line with a slope as $25000$
- B$\log\, k$ versus $\log\, T$ will give a straight line with a slope as $-2500$
- C$\log\, k$ versus $\log\, T$ will give a straight line with a slope as $-25000$
- ✓$\log\, k$ versus $1/T$ will give a straight line
