In the given figure, when galvanometer shows no deflection, the current (in $A$) flowing through $5\,\Omega $ resistance will be
Medium
Download our app for free and get started
Let current through $5\,\Omega $ resistance be $i$.
Then $i \times 25 = (2.1 - i)\,10$
$i = \frac{{10}}{{35}} \times 2.1 = 0.6\,A$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A $1\,m$ long copper wire carries a current of $1\,A$. If the cross section of the wire is $2.0\,mm ^{2}$ and the resistivity of copper is $1.7 \times 10^{-8}\,\Omega\,m$. the force experienced by moving electron in the wire is $\times 10^{-23}\,N$. (charge on electron $=1.6 \times 10^{-19}\,C$ )
The following circuit consist of a $5 \,\mu F$ capacitor, having charge $50 \,\mu C$ as shown. The switch is closed at $t=0$. The value of current in $2 \,M \Omega$ resistor at $t=0$ is ........... $\mu A$
The current density is a solid cylindrical wire of radius $R ,$ as a function of radial distance $r$ is given by $J ( r )= J _{0}\left(1-\frac{ r }{ R }\right) .$ The total current in the radial region $r =0$ to $r =\frac{ R }{4}$ will be
Circuit for the measurement of resistance by potentiometer is shown. The galvanometer is first connected at point $A$ and zero deflection is observed at length $P J = 10\ cm$ . In second case it is connected at point $C$ and zero deflection is observed at a length $30\ cm$ from $P$ . Then the unknown resistance $X$ is
Four identical cells each having an electromotive force $(e.m.f.)$ of $12\,V$, are connected in parallel. The resultant electromotive force $(e.m.f.)$ of the combination is .............. $V$
In the circuit shown below $E_1\, =4.0\, V$, $R_1\, = 2\,\Omega$, $E_2\, = 6.0\, V$, $R_2\, = 4\,\Omega$ and $R_3\, = 2\,\Omega$. The current $I_1$ is ............... $\mathrm{A}$