An electron revolves $6 × 10^{15}$ times/sec in circular loop. The current in the loop is
Easy
Download our app for free and get started
(a)$i = 6 \times {10^{15}} \times 1.6 \times {10^{ - 19}} = 0.96\,mA{\rm{.}}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1The potential difference across $8\, ohm$ resistance is $48\, volt$ as shown in the figure. The value of potential difference across $X$ and $Y$ points will be ............. $volt$View Solution
- 2In the given circuit, the current flowing through the resistance $20\ \Omega$ is $0.3 \mathrm{~A}$, while the ammeter reads $0.9 \mathrm{~A}$. The value of $\mathrm{R}_1$ is_____________ $\Omega$.View Solution
- 3Equivalent resistance between the points $A$ and $B$ is (in $\Omega$)View Solution
- 4In the circuit shown below, a student performing Ohm's law experiment accidently puts the voltmeter and the ammeter as shown in the circuit below. The reading in the voltmeter will be close to .......... $V$View Solution
- 5A storage battery is connected to a charger for charging with a voltage of $12.5\,\,Volts$. The internal resistance of the storage battery is $1\,\,\Omega$ . When the charging current is $0.5\,\,A$, the emf of the storage battery is: ............... $volts$View Solution
- 6In the given circuit, the current flowing through the resistance $20\ \Omega$ is $0.3 \mathrm{~A}$, while the ammeter reads $0.9 \mathrm{~A}$. The value of $\mathrm{R}_1$ is_____________ $\Omega$.View Solution
- 7For the circuit shown in the figure, the current $I$ will be .......$A$View Solution
- 8The figure below shows currents in a part of electric circuit. The current $i$ is ............. $amp$View Solution
- 9If three bulbs $60\,W$, $100\,W$ and $200\,W$ are connected in parallel, thenView Solution
- 10Two cells are connected in opposition as shown. Cell $\mathrm{E}_1$ is of $8 \mathrm{~V}$ emf and $2 \ \Omega$ internal resistance; the cell $E_2$ is of $2 \mathrm{~V}$ emf and $4\ \Omega$ internal resistance. The terminal potential difference of cell $\mathrm{E}_2$ is:View Solution
