The potential difference across $8\, ohm$ resistance is $48\, volt$ as shown in the figure. The value of potential difference across $X$ and $Y$ points will be ............. $volt$
Diffcult
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(a) The given circuit can be redrawn as follows
Resistance between $A$ and $B$ $ = \frac{{24 \times 8}}{{32}} = 6\,\Omega $
Current between $A$ and $B$ = Current between $X$ and $Y$ $ = i = \frac{{48}}{6} = 8\,A$
Resistance between $X$ and $Y$ $ = (3 + 10 + 6 + 1) = 20\,\Omega $
$==>$ Potential difference between $X$ and $Y$ = $8 × 20 = 160 \,V$
Resistance between $A$ and $B$ $ = \frac{{24 \times 8}}{{32}} = 6\,\Omega $
Current between $A$ and $B$ = Current between $X$ and $Y$ $ = i = \frac{{48}}{6} = 8\,A$
Resistance between $X$ and $Y$ $ = (3 + 10 + 6 + 1) = 20\,\Omega $
$==>$ Potential difference between $X$ and $Y$ = $8 × 20 = 160 \,V$
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(Round off to the Nearest Integer)