- ACatalytic hydrogenation.
- BTreatment with LiAlH4.
- CTreatment with pyridinium chlorochromate.
- DTreatment with KMnO4.
Explanation:
Alcohols are oxidized to aldehydes and finally to acids.
$\text{CH}_3\text{CH}_2\text{OH}\xrightarrow{[\text{O}]}\text{CH}_3\text{CHO}\xrightarrow{[\text{O}]}\text{CH}_3\text{COOH}$
Oxidations can be stopped at aldehyde stage by using puridinium chlorochromate (CrO3C5H5N.HCl)
$\text{CH}_3\text{CH}_2\text{OH}\xrightarrow{\text{PCC}}\text{CH}_3\text{CHO}$
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$(I)\,\,La(OH)_3$ is the least basic among hydroxides of lanthanides.
$(II) \,\,Zr^{4+}$ and $Hf^{4+}$ posses almost the same ionic radii.
$(III)\,\,Ce^{4+}$ can as an oxidizing agent
Which of the above is/are true ?

$\text { [en }= H _2 NCH _2 CH _2 NH _2 \text { ] }$
[Atomic number, $\mathrm{Cr}=24, \mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27$ ]