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RELATIONS AND FUNCTIONS — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsRELATIONS AND FUNCTIONS1 Mark
Question
Choose the correct answer from the given four options.
Let f : R → R be defined by $\text{f}(\text{x})=\begin{cases}2\text{x}:\text{x}>3\\\text{x}^2:1<\text{x}\leq3\\3\text{x}:\text{x}\leq1\end{cases}$ Then f(-1) + f(2) + f(4) is:
  1. 9
  2. 14
  3. 5
  4. none of these.
✓

Answer

  1. 9

Solution:

We are given that, $\text{f}(\text{x})=\begin{cases}2\text{x}:\text{x}>3\\\text{x}^2:1<\text{x}\leq3\\3\text{x}:\text{x}\leq1\end{cases}$

Now, f(-1) + f(2) + f(4) = 3(-1) + (2)2 + 2 × 4

= -3 + 4 + 8

= 9

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