Question
Define the term magnetic inclination. Deduce the relation connecting the horizontal component and inclination with the help of a diagram.

Answer

Magnetic Inclination: It is the angle made by resultant magnetic field of earth with the horizontal. It is also called angle of dip.

Relation: suppose $\overrightarrow{\text{Be}}$ is earth’s net magnetic field, $\theta$ is angle of dip. Resolving $\overrightarrow{\text{Be}}$ along horizontal and vertical directions; the horizontal component is H and vertical component is V. From fig.

$\therefore\text{ H=Be}\cos\theta$

This is the required relation.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

A rod is inserted as the core in the current-carrying solenoid of the previous problem.
  1. What is the magnetic intensity H at the centre?
  2. If the magnetization I of the core is found to be 0.12Nm, find the susceptibility of the material of the rod.
  3. Is the material paramagnetic, diamagnetic or ferromagnetic?
When we stir a liquid vigorously, it becomes warm. Is it a reversible process?
A particle goes in a circle of radius 2.0cm. A concave mirror of focal length 20cm is placed with its principal axis passing through the centre of the circle and perpendicular to its plane. The distance between the pole of the mirror and the centre of the circle is 30cm. Calculate the radius of the circle formed by the image.
What is Global Positioning System? Explain its working principle in brief.
At what distance should two charges, each equal to 1C, be placed so that the force between them equals your weight?
The density of an ideal gas is 1.25 × 10-3gcmat STP. Calculate the molecular weight of the gas.
Calculate de-Broglie wavelength associated with electron revolving in energy state $n=2$ of hydrogen atom.
Write and explain the super position principle (of waves).
A p-n junction germanium diode when forward biased has a drop of 0.3V which is assumed to be independent of current. The current in excess of 10mA through the diode produces a large Joule-heating which damages (burns) the diode. If we want to use a 1.5V battery to forward-bias the diode, what should be the value of resistor used in series with the diode, so that the maximum current does not exceed 6mA?

Is there any meaning of "Weight of the earth"?