Four bulbs $B_1 , B_2, B_3$ and $B_4$ of $100\, W$ each are connected to $220\, V$ main as shown in the figure. The reading in an ideal ammeter will be ............... $A$
JEE MAIN 2014, Diffcult
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Current in each bulb $=\frac{\text { Power }}{\text { Voltage }}$
$=\frac{100}{220}=0.45\, \mathrm{A}$
Current through ammeter
$=0.45 \times 3=1.35\, \mathrm{A}$
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