Four equal resistance dissipated $5 \,W$ of power together when connected in series to a battery of negligible internal resistance. The total power dissipated in these resistance when connected in parallel across the same battery would be ........... $W$
  • A$125$
  • B$80$
  • C$20$
  • D$5$
Easy
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    For a cell terminal $P.D.$ is $2.2\;V$ when circuit is open and reduces to $1.8\;V$ when cell is connected to a resistance of $R = 5\,\Omega $. Determine internal resistance of cell $(r)$ is then ........ $\Omega$
    View Solution
  • 2
    A generator has armature resistance of $0 .1\,\Omega $ and develops an induced emf of $120 \,V$ when driven at its rated speed. Its terminal voltage when a current of $50\,A$ is being drawn is ................. $V$
    View Solution
  • 3
    Length of a hollow tube is $5\,m$, it’s outer diameter is $10\, cm$ and thickness of it’s wall is $5\, mm$. If resistivity of the material of the tube is $1.7 \times 10^{-8} \,\Omega m$ then resistance of tube will be
    View Solution
  • 4
    The supply voltage to room is $120\ V$. The resistance of the lead wires is $6\,\Omega$ . A $60\ W$ bulb is already switched on. What is the decrease of voltage across the bulb, when a $240\ W$ heater is switched on in parallel to the bulb? ............. $V$
    View Solution
  • 5
    There are $n$ similar conductors each of resistance $R$. The resultant resistance comes out to be $x$ when connected in parallel. If they are connected in series, the resistance comes out to be
    View Solution
  • 6
    During lighting, a current pulse, shown in figure, flows from the cloud at a height $1.5\ km$ to the ground. If the breakdown electric field of humid air is about $400\ kVm^{-1}$ , the energy released during lighting would be (in unit of $10^9\ J$ )
    View Solution
  • 7
    In the figure shown, what is the current (in Ampere) drawn from the battery ? You are given $R_1 = 15\,\Omega $$,R _2 = 10\,\Omega ,$$ R_3 = 20\,\Omega ,$$ R_4 = 5\,\Omega ,$$R_5 = 25\,\Omega ,$$R_6 = 30\,\Omega , $$E = 15\,V$
    View Solution
  • 8
    Constantan wire is used in making standard resistances because its
    View Solution
  • 9
    In the circuit shown below the resistance of the galvanometer is $20\, \Omega$ . In which case of the following alternatives are the currents arranged strictly in the decreasing order
    View Solution
  • 10
    Find the current in the loop.
    View Solution