In the circuit as shown in figure the
Medium
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$\frac{1}{{R'}} = \frac{1}{{10}} + \frac{1}{{10}} + \frac{1}{{20}}$$ \Rightarrow R' = \frac{{20}}{5} = 4\;\Omega $
Now using ohm’s law $i = \frac{{25}}{{R + R'}}$$ \Rightarrow 0.5 = \frac{{25}}{{R + 4}}$
$ \Rightarrow R + 4 = \frac{{25}}{{0.5}} = 50$ $ \Rightarrow R = 50 - 4 = 46\;\Omega $
Current through $20\,\Omega $ resistor $ = \frac{{0.5 \times 5}}{{20 + 5}} = \frac{{2.5}}{{25}} = 0.1\,A$
Potential difference across middle resistor
$=$ Potential difference across $20\,\Omega $$ = 20 \times 0.1 = 2\,V$
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