In the circuit shown in the adjoining figure, the reading of ammeter $A$ is ................ $\mathrm{A}$
Medium
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Equivalent of $2\, \Omega \,\,4\, \Omega $ and $ 12\, \Omega$ in parallel is $\frac{12}{10}$
$\therefore $ equivalent resistance $=\frac{12}{10}+\frac{3}{10}=\frac{15}{10}=1.5 $ $\Omega $
reading of ammeter $=\frac{1.5}{1.5}=1 \mathrm{\,A}$
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